316,239 views
44 votes
44 votes
Renee wants to solve the system of equations. Which number can she multiply the first equation by so that when the two equations are added together, the y term is eliminated?

Two-thirds x + one-fifth y = 6

One-sixth x minus 3 y = 8

A.-15
B.-5
C.5
D.15

User Dmoney
by
2.8k points

2 Answers

24 votes
24 votes

Answer:

Multiply the first equation by 15 (Answer D)

Explanation:

Writing these equations symbolically, we have:

(2/3)x + (1/5)y = 6

(1/6)x - 3y = 8

Which number can she multiply the first equation by so that when the two equations are added together, the y term is eliminated? After this multiplication, we should have +3y in the first equation; then 3y - 3y = 0 as desired. The coefficient of the y term in the first equation is (1/5), whereas we want it to be +3.

Multiplying the first equation by 15, we get 10x + 3y = 90.

Then our system is:

10x + 3y = 90

(1/6)x - 3y = 8

---------------------

(61/6)x = 98 (the variable y has been temporarily eliminated).

User NathanOliver
by
3.1k points
8 votes
8 votes

Answer:

eliminate D

Explanation:

User Easwee
by
3.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.