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It's urgent. I need help to know the oxidation numbers and what is the oxidation and reduction part of this equation Fe + H2SO4= Fe2(SO4)3 + H2

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In the given equation: Fe + H2SO4 = Fe2(SO4)3 + H2

To determine the oxidation numbers, we assign oxidation numbers to each element in the equation.

1. Fe: The oxidation number of Fe is 0 since it is in its elemental form.

2. H2SO4:
- H has an oxidation number of +1.
- S has an oxidation number of +6 since it is in the sulfate ion (SO4)2-.
- O has an oxidation number of -2.

3. Fe2(SO4)3:
- Fe has an oxidation number of +3 since it is in the Fe2+ ion.
- S has an oxidation number of +6 since it is in the sulfate ion (SO4)2-.
- O has an oxidation number of -2.

4. H2:
- H has an oxidation number of 0 since it is in its elemental form.

Now, let's analyze the oxidation and reduction parts of the equation:

Oxidation: Fe is oxidized from an oxidation number of 0 to +3 in Fe2(SO4)3.

Reduction: H2SO4 is reduced. The sulfur (S) in H2SO4 goes from an oxidation number of +6 to +4 in Fe2(SO4)3, and the hydrogen (H) in H2SO4 goes from an oxidation number of +1 to 0 in H2.

Overall, in this equation, Fe is oxidized, and H2SO4 is reduced.
User Pavitar Singh
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