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Identify the equation of the line that passes through the pair of points (4, −8) and (7, −6) in slope-intercept form.

User Indrek
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To find the equation of the line that passes through the points (4, -8) and (7, -6), we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

First, let's find the slope of the line. The formula for slope (m) is:

m = (y2 - y1) / (x2 - x1)

Using the coordinates (4, -8) and (7, -6):

m = (-6 - (-8)) / (7 - 4)
= 2 / 3

Now that we have the slope, we can substitute it into the slope-intercept form equation:

y = (2/3) * x + b

To find the y-intercept (b), we can substitute the coordinates of one of the given points into the equation. Let's use the point (4, -8):

-8 = (2/3) * 4 + b
-8 = 8/3 + b

To solve for b, we subtract 8/3 from both sides:

-24/3 - 8/3 = b
-32/3 = b

So the equation of the line in slope-intercept form is:

y = (2/3) * x - (32/3)
User Harsha Kumar Reddy
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