Maths max points area question for grade 7

Question

asked Dec 21, 2024 135k views

1 Answer

Ezgar · Answer 1 · 2024-12-27T08:57:27+0000

Answer:

$\textsf{ Area of Park is } \sf \underline{870 m^2.}$

Explanation:

Let's find the area find dividing the parks in two triangles.

See Attachment:

In Lower triangle: ABE

Perpendicular = AE = 11m

Base = AB = 60 m

Hypotenuse = BE = 61 m

Since we have,

$\sf \textsf{Area of right angled triangle }= (1)/(2)Perpendicular* Base$

Substituting value

$\sf \textsf{Area of right angled triangle ABE }= (1)/(2)(11* 60) = 330 m^2$

$\dotfill$

In Upper Triangle: ABC

Base = AB = 60 m

Height = CD = 18 m

We have,

$\sf \textsf{Area of triangle }= (1)/(2)Base* height$

Substituting value

$\sf \textsf{Area of triangle ABC }= (1)/(2)(60 * 18) = 540 m^2$

$\dotfill$

Now,

Area of park = Area of Lower triangle ABE + Area Upper Triangle ABC

$\textsf{Area of Park = }\sf 330 m^2 + 540 m^2=870m^2$

Therefore,
$\textsf{ Area of Park is } \sf \underline{870 m^2.}$