Question

. The height of the Benedict Goh Tower is 762.54 m. The height of the building is measured from the sea level to the highest point of the building. Originally, the position of a submarine is at 123 metres below the sea level. The submarine goes up 3 metres every 2 seconds. Find the vertical distance between the submarine and the highest point of the building after 12 seconds.

Answer 1

To find the vertical distance between the submarine and the highest point of the building after 12 seconds, we need to calculate the change in height for both the submarine and the building separately, and then find the difference between them.

1. Height change for the submarine:

The submarine goes up 3 meters every 2 seconds, so in 12 seconds:

Number of intervals: 12 seconds / 2 seconds = 6 intervals

Height change: 6 intervals * 3 meters = 18 meters

2. Height of the building:

The height of the building is 762.54 meters.

Now, let's calculate the total vertical distance between the submarine and the highest point of the building:

Total distance = Height of building - Height change for submarine

Total distance = 762.54 meters - 18 meters

Total distance = 744.54 meters

Therefore, the vertical distance between the submarine and the highest point of the building after 12 seconds is 744.54 meters.