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What is the pOH of a 7.9 x 10(-4)m OH- solution?
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What is the pOH of a 7.9 x 10(-4)m OH- solution?

User Kamalav
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1 Answer

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pOH is defined as -log([OH-])

pOH = -log([OH-]) = -log(7.9 x 10^-4) = 3.1

Hope that helps! :)
User Tarmiac
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