Question

Which equation is the inverse of 5y+4 = (x+3)² + 1/2?

A. y = 1/5x²+6/5x+11/10
B. y = 3±√(5x+7/2)
C. -5y-4 = -(x+3)²-1/2
D. y=-3±√(5x+7/2)

Answer 1

Hi,

Answer D

Explanation:

`5y+4=(x+3)^2+(1)/(2) \\Exchanging\ x\ and\ y:\\5x+4=(y+3)^2+(1)/(2) \\(y+3)^2=5x+4-(1)/(2) \\(y+3)^2=5x+(7)/(2) \\y+3=\pm\sqrt{5x+(7)/(2) } \\\\y=-3\pm\sqrt{5x+(7)/(2) } \\\\Answer\ D`