Question

There are 100 cars in a park, 28 of them are blue and 34 are red. if a car is selected at random from the car, what is the probability that is neîther blue nor red?

Answer 1

`(19)/(50)`

Explanation:

Number of cars which are nighter blue nor red

100-(28+34)= 38 cars

So the probability,

`(38)/(100) = (19)/(50)`