Question

fixed container with 0.255 moles of gas. if container volume is 0.748 L and the temp is 301.15K, what is pressure in atm?

Answer 1

To calculate the pressure of the gas using the ideal gas law (PV = nRT), where:

P is pressure,

V is volume,

n is the number of moles,

R is the ideal gas constant (0.08206 L atm / K mol),

T is temperature in Kelvin.

Given:

Volume (V) = 0.748 L

Number of moles (n) = 0.255 moles

Temperature (T) = 301.15 K

Ideal gas constant (R) = 0.08206 L atm / K mol

Plug in these values into the ideal gas law equation:

P * V = n * R * T

Solve for pressure (P):

P = (n * R * T) / V

Now, plug in the values:

P = (0.255 mol * 0.08206 L atm / K mol * 301.15 K) / 0.748 L

P ≈ 8.328 atm

Therefore, the pressure of the gas in the fixed container is approximately 8.328 atm.