Final Answer:
1. a. The null hypothesis
for testing the claim is that the proportion of college students who believe online education is as good as or superior to traditional face-to-face instruction is equal to 80%, i.e., p = 0.80.
b. The rejection region for a two-tailed test conducted at
is Z < -1.645 or Z > 1.645.
Step-by-step explanation:
a. The null hypothesis
is a statement of no effect or no difference. In this case, it is stated as p = 0.80, where p is the proportion of college students who believe online education is as good as or superior to traditional face-to-face instruction. This assumes that 80% is the baseline or expected proportion, and any deviation from this value will be considered in the alternative hypothesis.
b. The rejection region for a two-tailed test at
involves finding critical values on both tails of the standard normal distribution. For a significance level of 0.10, the critical values are Z < -1.645 or Z > 1.645 . If the test statistic falls in either of these regions, the null hypothesis is rejected. This level of significance suggests a relatively high confidence level of 90% in a two-tailed test.
In summary, the null hypothesis is a statement of equality, assuming that 80% of college students find online education as good as or superior to traditional instruction. The rejection region in a two-tailed test at
is determined by critical values of Z , which areZ < -1.645 or Z > 1.645 . These critical values define the boundaries for rejecting the null hypothesis based on the level of significance.