Question

3х(Х+5)=5х(12-Х)-5=
Помогите пожалуйста

Answer 1

To solve the given equation:

3x(x + 5) = 5x(12 - x) - 5

First, let's simplify both sides of the equation step by step:

Distribute on both sides:

• 3x^2 + 15x = 60x - 5x^2 - 5

Combine like terms on the right side:

• 3x^2 + 15x = 55x - 5

Move all terms to one side of the equation:

• 3x^2 + 15x - 55x + 5 = 0

Simplify:

• 3x^2 - 40x + 5 = 0

Now, you have a quadratic equation in standard form. To solve for x, you can use the quadratic formula:

• x = (-b ± √(b^2 - 4ac)) / 2a

In this case, the coefficients are:

• a = 3
• b = -40
• c = 50

Plug these values into the quadratic formula:

• x = (-(-40) ± √((-40)^2 - 4 * 3 * 5)) / (2 * 3)
• x = (40 ± √(1600 - 60)) / 6
• x = (40 ± √(1540)) / 6
• x = (40 ± √(4 * 385)) / 6
• x = (40 ± 2√385) / 6

So, the solutions for the equation are:

• x = (40 + 2√385) / 6
• x = (40 - 2√385) / 6

These are the values of x that satisfy the given equation.