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1 vote
Simplify fraction with 6 minus 3 times 6 in the numerator and the cube root of 8 plus 9 in the denominator.

2 Answers

3 votes

Answer:

i understand (6 -3*6)/(
\sqrt[3]{8} +9) =

(6-18)/(2+9)= -12/11

Explanation:

User Lewis Machilika
by
8.1k points
0 votes

Answer:


\boxed{\sf- (12)/(11)}

Explanation:

According to the question:

Fraction with 6 minus 3 times 6 in the numerator and the cube root of 8 plus 9 in the denominator.

We can write it mathematically as:


\sf \frac{6-3* 6}{\sqrt[3]{8}+9}

Simplifying the numerator, we get:


\sf \sf \frac{6-3* 6 }{\sqrt[3]{8}+9}=\frac{-12}{\sqrt[3]{8}+9}

Simplifying the denominator, we get:


\sf \frac{-12}{\sqrt[3]{8}+9} = \frac{-12}{\sqrt[3]{2^3}+9} = (-12)/(2+9)=(-12)/(11)

Therefore, the simplified expression is:


\boxed{\sf- (12)/(11)}

So, the answer is
\sf -(12)/(11).

User ErniBrown
by
8.0k points

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