Question

Simplify fraction with 6 minus 3 times 6 in the numerator and the cube root of 8 plus 9 in the denominator.

Answer 1

i understand (6 -3*6)/(
`\sqrt[3]{8} +9)` =

(6-18)/(2+9)= -12/11

Explanation:

Answer 2

`\boxed{\sf- (12)/(11)}`

Explanation:

According to the question:

Fraction with 6 minus 3 times 6 in the numerator and the cube root of 8 plus 9 in the denominator.

We can write it mathematically as:

`\sf \frac{6-3* 6}{\sqrt[3]{8}+9}`

Simplifying the numerator, we get:

`\sf \sf \frac{6-3* 6 }{\sqrt[3]{8}+9}=\frac{-12}{\sqrt[3]{8}+9}`

Simplifying the denominator, we get:

`\sf \frac{-12}{\sqrt[3]{8}+9} = \frac{-12}{\sqrt[3]{2^3}+9} = (-12)/(2+9)=(-12)/(11)`

Therefore, the simplified expression is:

`\boxed{\sf- (12)/(11)}`

So, the answer is
`\sf -(12)/(11)`.