Final answer:
The binary relation R is symmetric but not reflexive, not definitively transitive, and not antisymmetric, as it fails to meet the necessary conditions for these properties with the exception of symmetry.
Step-by-step explanation:
To determine if the given binary relation R where (x, y) ∈ R if and only if xy ≥ 10 is reflexive, symmetric, transitive, or antisymmetric, we need to evaluate it based on the definitions of those properties:
- Reflexive: A relation R is reflexive if every element is related to itself. For (x, x) to be in R, we would need xx ≥ 10, which is true for all x ≥ 4. However, for x = 1, 2, or 3, it is not true that xx ≥ 10, so R is not reflexive.
- Symmetric: A relation is symmetric if for every (x, y) in R, we also have (y, x) in R. Given that xy ≥ 10, we can also say yx ≥ 10 (since multiplication is commutative), so R is symmetric.
- Transitive: A relation is transitive if whenever (x, y) and (y, z) are in R, then (x, z) is also in R. If xy ≥ 10 and yz ≥ 10, then xz could be smaller or equal to 10 if y is less than 10. Thus, we cannot definitely say the relation is transitive without further information about the values of x, y, and z.
- Antisymmetric: A relation is antisymmetric if for every (x, y) and (y, x) in R where x ≠ y, it holds that R contains only one of these two elements. Since R is already established as symmetric, it cannot be antisymmetric.
In conclusion, the relation R on the set of all positive integers where (x, y) ∈ R if and only if xy ≥ 10 is symmetric but not reflexive, not definitively transitive, and not antisymmetric.