Question

A bag contains 44 red balls and 55 blue bals rehmen picks 22balls a lt a random. Calculte the probability tahy he selects the same colored ball each time given that after each time a ball is selected it is replaced

Answer 1

41/81.

Explanation:

There are a total of 99 balls.

On the first pick the probability he picks a red ball is 44/99 = 4/9.

On the second pick the probability is also 4/9 as the first ball is replaced,

So probability he picks 22 reds = (4/9)^2 = 16/81.

If he picks 2 blue balls probability = (5/9) * 2 = 25/81.

So the required probability ( 2 reds Or 2 blues) = 16/81 + 25/81

= 41/81.