Question

how much enthalpy/heat is transferred when 0.5113 g of ammonia(NH3) reacts with excess oxygen according to the following equation? is the reaction exo or endo

Answer 1

To determine the amount of heat transferred in the reaction, you need to know the enthalpy change (∆H) per mole of the reaction. Since the equation for the reaction is not provided, it's not possible to determine the exact value of ∆H.

However, assuming that the equation for the reaction is:

4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)

From the balanced equation, we can see that the stoichiometric ratio is 4:5 between NH3 and O2. Therefore, we can calculate the number of moles of NH3:

Number of moles of NH3 = Mass of NH3 (g) / Molar mass of NH3 (g/mol)

Number of moles of NH3 = 0.5113 g / 17.03 g/mol (molar mass of NH3)

Now, to determine the amount of heat transferred, we need the ∆H value. If the value of ∆H is positive, it means the reaction is endothermic (heat absorbed), and if the value of ∆H is negative, it means the reaction is exothermic (heat released).

Therefore, without the ∆H value, it is impossible to determine the specific amount of heat transferred or whether the reaction is exothermic or endothermic.