Final answer:
The joint distribution of W1 and W2 can be expressed as f(w1,w2) = f(y1)f(y2) / |J|, where f(y1) and f(y2) are the probability density functions of Y1 and Y2.
Step-by-step explanation:
To find the joint distribution of W1 and W2, we need to find the mean and variance of W1 and W2. Using the properties of the normal distribution, we can calculate:
E(W1) = E(Y1 + 2Y2) = E(Y1) + 2E(Y2) = 1 + 2(2) = 5
Var(W1) = Var(Y1 + 2Y2) = Var(Y1) + 4Var(Y2) = 3 + 4(5) = 23
E(W2) = E(4Y1 - Y2) = 4E(Y1) - E(Y2) = 4(1) - 2 = 2
Var(W2) = Var(4Y1 - Y2) = 16Var(Y1) + Var(Y2) = 16(3) + 5 = 53
The joint distribution of W1 and W2 is given by:
f(w1,w2) = P(W1 = w1, W2 = w2)
Using the properties of independent normal random variables, we can express the joint distribution as follows:
f(w1,w2) = f(y1,y2) / |J|
where f(y1,y2) is the joint probability density function of Y1 and Y2, and |J| is the determinant of the Jacobian matrix. Since Y1 and Y2 are independent, f(y1,y2) = f(y1)f(y2), where f(y1) and f(y2) are the probability density functions of Y1 and Y2, respectively.
Therefore, the joint distribution of W1 and W2 can be expressed as:
f(w1,w2) = f(y1)f(y2) / |J|