Question

What is the initial pressure of a gas in a

0.5650 L container if the pressure is
715.1 torr in a 1.204 L container?
P = [?] torr
Assume that the number of moles and the
temperature remain constant.

Answer 1

We can use the combined form of Boyle's law for this problem, which states that for a given amount of gas at a constant temperature, the product of pressure and volume is a constant:

P1 * V1 = P2 * V2

Where:

P1 = Initial pressure of the gas

V1 = Initial volume of the gas container

P2 = Pressure of the gas in a different container (given as 715.1 torr)

V2 = Volume of the gas container with the different pressure

Given:

V1 = 0.5650 L

P2 = 715.1 torr

V2 = 1.204 L

Now we can solve for the initial pressure, P1:

P1 = (P2 * V2) / V1

P1 = (715.1 torr * 1.204 L) / 0.5650 L

P1 ≈ 1521.12 torr

The initial pressure of the gas in the 0.5650 L container is approximately 1521.12 torr.