Answer:
0.56 Liters.
Step-by-step explanation:
First, we need to determine the number of moles of KHCO3 and HCl used in the reaction. The molar mass of KHCO3 is approximately 100.12 g/mol, and for HCl, it's approximately 36.46 g/mol. Therefore, the number of moles of KHCO3 is 2.5g / 100.12 g/mol ≈ 0.025 mol, and the number of moles of HCl is 5.2g / 36.46 g/mol ≈ 0.143 mol.
In the reaction, one mole of KHCO3 reacts with one mole of HCl to produce one mole of CO2. Therefore, the amount of CO2 produced will be limited by the reagent present in the least amount, which in this case is KHCO3.
So, approximately 0.025 mol of CO2 will be produced. Given that the volume of one mole of any gas at standard temperature and pressure (STP) is approximately 22.4 liters, the volume of CO2 produced can be calculated as 0.025 mol * 22.4 L/mol ≈ 0.56 Liters.