28.7k views
3 votes
Below is the graph of a trigonometric function. It intersects its midline at (-10.7,-3) and again at (-5.5,-3)

What is the period of the function? Give an exact value.

Below is the graph of a trigonometric function. It intersects its midline at (-10.7,-3) and-example-1
Below is the graph of a trigonometric function. It intersects its midline at (-10.7,-3) and-example-1
Below is the graph of a trigonometric function. It intersects its midline at (-10.7,-3) and-example-2
User Abiola
by
8.3k points

1 Answer

2 votes

Answer:

Explanation:

The period of the function is how long 1 cycle is. On the graph, we are only given half of one cycle, which is 5.2 units long; that means that the whole cycle is that value times 2 or 10.4 units. The period formula is


period=(2\pi)/(10.4) which is the same thing as


period=(2\pi)/((52)/(5) )which gives us


period=(2\pi)/(1)*(5)/(52) and


period=(10\pi)/(52)=(5\pi)/(26)

User Shmack
by
7.9k points