Answer:
Explanation: The decay of a radioactive atom can be represented using a nuclear equation. In this case, the radioactive atom is Americium-210, which decays by emitting an alpha particle. An alpha particle consists of two protons and two neutrons, so its symbol is "α" or "He" (helium nucleus). The resulting daughter nucleus is the product of the decay.
The nuclear equation for the alpha decay of Americium-210 (210 84 AM) would be:
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210 84 AM → 4 2 He + Daughter Nucleus
In this equation:
The numbers represent the atomic mass (superscript) and atomic number (subscript) of the particles/nuclei.
"AM" represents Americium-210, which has an atomic number of 84 and an atomic mass of 210.
"He" represents the alpha particle, which has an atomic number of 2 and an atomic mass of 4.
"Daughter Nucleus" represents the resulting nucleus after the alpha particle emission. The specific identity of the daughter nucleus would depend on the decay process and would need to be determined based on the known decay products of Americium-210.
Please note that without more information about the specific daughter nucleus resulting from the decay of Americium-210, the equation cannot be fully balanced or complete. The equation above represents the general form of alpha decay for Americium-210.