Question

Use the given conditions to write an equation for the line in slope-intercept form. Passing through (2,−5) and perpendicular to the line whose equation is 6x−5y=9

Answer 1

y = -5/6 x - 10/3

Explanation:

6x − 5y = 9

Solve for y to find slope.

-5y = -6x + 9

y = 6/5 x - 9/5

slope of perpendicular line = 6/5

We want a line perpendicular to a line whose slope is 6/5, so our line must have slope -5/6.

y = mx + b

y = -5/6 x + b

-5 = -5/6 × 2 + b

-15/3 = -5/3 + b

-10/3 = b

y = -5/6 x - 10/3