Question

If 2.18 gAr are added to 2.30 atmHe in a 2.00 L cylinder at 27.0∘ C, what is the total pressure of the resulting gaseous mixture? P_tot atm

Answer 1

The total pressure is 3.10 atm.

Step-by-step explanation:

Dalton's law of partial pressures states that the total pressure is equal to the sum of the partial pressures. We simply add the two pressures together:
Ptot = 2.33 atm + 0.77 atm = 3.10 atm

Answer 2

The total pressure of the resulting gaseous mixture is 4.48 atm.

Step-by-step explanation:

Dalton's law of partial pressures states that the total pressure is equal to the sum of the partial pressures. In this case, the partial pressure of Ar is 2.30 atm and the partial pressure of He is 2.18 g. By adding these two partial pressures together, you can find the total pressure of the resulting gaseous mixture.

Total pressure = 2.30 atm + 2.18 atm = 4.48 atm