Question

The vapor pressure of water at 80 °C is 0.468 atm. Calculate the vapor pressure in mmHg and torr. Round each of your answers to 3 significant digits.

Answer 1

To convert the vapor pressure of water from atm to mmHg and torr, multiply the value in atm (0.468) by the conversion factor 760, resulting in 355.68 mmHg and 355.68 torr.

Step-by-step explanation:

To convert the vapor pressure of water from atm to mmHg and torr, we can use the conversion factors that 1 atm is equivalent to 760 mmHg and also to 760 torr.

First, calculate the vapor pressure in mmHg:

0.468 atm × 760 mmHg/atm = 355.68 mmHg

Then, calculate the vapor pressure in torr:

Since 1 mmHg is exactly equal to 1 torr, the vapor pressure in torr will be the same as in mmHg:

355.68 torr

Both results are rounded to three significant digits, as requested.

Answer 2

The vapor pressure of water at 80 °C is 0.468 atm, which is equivalent to 356 mmHg and 356 torr after rounding to three significant digits, using the conversion factor that 1 atm equals 760 mmHg or torr.

Step-by-step explanation:

To convert the vapor pressure of water from atm to mmHg and torr, we need to use the conversion factors that 1 atm is equal to 760 mmHg and 1 atm is equal to 760 torrs since mmHg and torr are equivalent units of pressure.

Given that the vapor pressure of water at 80 °C is 0.468 atm, the conversions are as follows:

• Vapor pressure in mmHg: 0.468 atm × 760 mmHg/atm = 355.68 mmHg
• Vapor pressure in torr: 0.468 atm × 760 torr/atm = 355.68 torr

After rounding each of these to three significant digits, the vapor pressure of water at 80 °C is:

• 356 mmHg
• 356 torr