Question

Voltage Drop Across Transmission Lines Part A A pair of power transmission lines each have a 0.890 A resistance and carry an rms current of 620 A over 9.12 km. If the rms input voltage is 36.6 kV, calculate the rms voltage at the other end. a Submit Aww Tries 0/6 Part B Calculate the power input. Submit Arower Tries 0/6 Part C Calculate the power loss in the lines. Submit Antwer Tries 0/6 Part Calculate the power output submit Tries 0/6

Answer 1

The voltage drop across transmission lines can be calculated using Ohm's Law.

Step-by-step explanation:

In order to calculate the voltage drop across transmission lines, we need to use Ohm's Law which states that V = IR, where V is the voltage, I is the current, and R is the resistance.

Using the given values, we have:

V = (0.890 A)(9.12 km) = 8.1168 kV (rms)

Therefore, the rms voltage at the other end is 8.1168 kV.

Answer 2

To calculate the rms voltage at the other end, subtract the voltage drop from the input voltage. To calculate the power input, multiply the current and voltage. To calculate the power loss, use the formula P = I²R. To calculate the power output, subtract the power loss from the power input.

Step-by-step explanation:

In order to calculate the rms voltage at the other end, we can use Ohm's Law, which states that V = IR, where V is the voltage, I is the current, and R is the resistance. Since we are given the resistance of the transmission lines (0.890 A) and the rms current (620 A), we can calculate the voltage drop across the transmission lines by multiplying the resistance by the current: 0.890 A * 620 A = 551.8 V. To find the rms voltage at the other end, we subtract this voltage drop from the input voltage: 36.6 kV - 0.5518 kV = 36.05 kV.

To calculate the power input, we can use the formula P = IV, where P is the power, I is the current, and V is the voltage. Given the rms current (620 A) and the rms input voltage (36.6 kV), we can calculate the power input: 620 A * 36.6 kV * 1000 = 22,692,000 W = 22,692 MW.

To calculate the power loss in the lines, we can use the formula P = I²R, where P is the power, I is the current, and R is the resistance. Given the resistance of the transmission lines (0.890 A) and the rms current (620 A), we can calculate the power loss: 620 A * 620 A * 0.890 A = 343,644 W = 343.644 kW.

Finally, to calculate the power output, we subtract the power loss from the power input: 22,692 MW - 343.644 kW = 22,348.356 MW.