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(10 pts) You need to design a toroid with square windings such that the magnetic field in the centre of the windings is 0.0020 T, and the side length of a square winding is 3 cm. The wire you are using can carry a current of at most 0.5 A. The magnetic field anywhere inside the windings must be at least 0.0016 T. What is the minimum number of windings you will need? You may assume the result that a toroid with N windings has a magnetic field at a distance r inside the toroid that has magnitude B where I is the 2πη current in the coils and po = 41 x 10 "TmA. HONI

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To find the minimum number of windings needed, we can use the formula for the magnetic field inside a toroid, given by B = (μ₀ * N * I) / (2π * r), where B is the magnetic field, μ₀ is the permeability of free space (4π x 10^-7 Tm/A), N is the number of windings, I is the current, and r is the radius.

In this case, we want the magnetic field in the center of the windings to be 0.0020 T. Since the center of the windings is the same as the radius of the toroid, we can rewrite the formula as B = (μ₀ * N * I) / (2π * R), where R is the radius.

We also know that the wire can carry a current of at most 0.5 A and that the magnetic field anywhere inside the windings must be at least 0.0016 T.

To find the minimum number of windings, we can rearrange the formula to solve for N:

N = (2π * R * B) / (μ₀ * I)

Substituting the given values, we have:

N = (2π * 0.03 m * 0.0020 T) / (4π x 10^-7 Tm/A * 0.5 A)

Simplifying the expression, we get:

N = (0.06 * 0.0020) / (4 x 10^-7 * 0.5)

N = 0.00012 / 2 x 10^-7

N = 0.00012 x 5 x 10^6

N = 600 windings

Therefore, the minimum number of windings needed is 600.
User Leonardo Nomdedeu
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