Question

The mole fraction of chromium(II) nitrate, Cr(NO3)2, in an aqueous solution is 5.69x10-2. The percent by mass of chromium(II) nitrate in the solution is | %.

Answer 1

The percent by mass of chromium(II) nitrate in the solution is 9.23%.

Step-by-step explanation:

The mole fraction of chromium(II) nitrate, Cr(NO3)2, in an aqueous solution is 5.69x10-2. To calculate the percent by mass of chromium(II) nitrate in the solution, we need to know the molar mass of the compound and the mass of the solution. Let's assume we have 100 grams of the solution. The molar mass of Cr(NO3)2 is 162.01 g/mol. The mass of chromium(II) nitrate in the solution is then 0.0569 x 162.01 g = 9.23 g. Therefore, the percent by mass of chromium(II) nitrate in the solution is 9.23%.

Answer 2

To calculate the percent by mass of chromium(II) nitrate in the solution, use the formula (mass of solute ÷ mass of solution) x 100%. The mole fraction of chromium(II) nitrate is 5.69x10-2.

Step-by-step explanation:

To find the percent by mass of chromium(II) nitrate in the solution, we need to calculate the mass of chromium(II) nitrate present in the solution. The mole fraction of chromium(II) nitrate is 5.69x10-2. The mole fraction of a component in a solution is equal to the moles of that component divided by the total moles of all components in the solution.

The percent by mass can be calculated using the formula:

Percent by mass = (mass of solute ÷ mass of solution) x 100%

Let's assume the mass of the solution is 100 grams. Therefore, the mass of chromium(II) nitrate would be (5.69x10-2) x 100 grams. Use this value to calculate the percent by mass.