Question

1+2+4+8+16+32+64 What is the series in sigma notation?

Answer 1

Answer:
`\[\sum_(k=0)^(6) 2^k\]`

Explanation:

The given series is a geometric sequence where the first term
`\( a = 1 \)` and the common ratio
`\( r = 2 \)`. The sum of the first
`\( n \)` terms of a geometric sequence can be represented in sigma notation as:

`\[\sum_(k=0)^(n-1) ar^k\]`

In this case, since there are 7 terms, \( n = 7 \), \( a = 1 \), and \( r = 2 \), the sum can be represented as:

`\[\sum_(k=0)^(6) 2^k\]`