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Are the lines 2x+3y-6=0 and -6x+9y+10=0 parallel, perpendicular or neither?

User Mirrana
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Answer:

Neither

Explanation:

Relationship of slopes with parallel and perpendicular lines:

Parallel lines:

  • The slopes of parallel lines have the same slope.

Perpendicular lines:

  • The slopes of perpendicular lines are negative reciprocals of each other.

This is shown by the formula m2 = -1 / m1, where

  • m2 is the slope of one line,
  • and m2 is the slope of the other line.

Identifying the forms of 2x + 3y - 6 = 0 and -6x + 9y + 10 = 0:

Both 2x + 3y - 6 = 0 and -6x + 9y + 10 = 0 are in the general form of a line, whose general equation is given by:

Ax + By + C = 0, where

  • A, B, and C are constants.

Determining the slopes of 2x + 3y - 6 = 0 and -6x + 9y + 10 = 0:

The easiest way to identify the slope is to convert form general from to slope-intercept form, whose general equation is given by:

y = mx + b, where

  • m is the slope,
  • and b is the y-intercept.

Converting from general form to slope-intercept form:

Thus, we can convert form general form to slope-intercept form by isolating y on the left-hand side:

Converting 2x + 3y - 6 = 0 to slope-intercept form:

(2x + 3y - 6 = 0) - 2x + 6

(3y = -2x + 6) / 3

y = -2/3x + 2

Converting -6x + 9y + 10 = 0 to slope-intercept form:

(-6x + 9y + 10 = 0) + 6x - 10

(9y = 6x - 10) / 9

y = 2/3x - 10/9

Since the slopes are not the same nor are they negative reciprocals of each other, the lines are neither parallel nor perpendicular.

User Shaunsantacruz
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