24.8k views
1 vote
Pls helps just solve the first one or if you can do both

Pls helps just solve the first one or if you can do both-example-1
User Sanzy
by
7.7k points

1 Answer

0 votes

Answer: HENCE, ((A)): x = 2, ((B)): x = 10

((A)): -5(4x - 2 ) = -2(3 + 6x): X = 2

((B)): 5(2x + 6) = -4( -5 - 2x) + 3x: X = 10

Explanation:

SOLVE EACH EQUATION:

  • PROBLEM - ((A)):

-5(4x - 2 ) = -2(3 + 6x)

  • APPLY THE DISTRIBUTIVE PROPERTY:
    -20x + 10 = -6 - 12x
  • REARRANGE VARIABLES TO THE LEFT SIDE OF THE EQUATION:
    -20x + 12x = -6 - 10
  • COMBINE LIKE TERMS:

-8x = -6 - 10

  • CALCULATE THE SUM OR DIFFERENCE:

-8x = -16

  • DIVIDE BOTH SIDES:

x = -16 / -8

  • DETERMINE THE SIGN FOR MULTIPLICATION OR DIVISION:

x = 16 / 8

  • CROSS OUT COMMON FACTORS:

x = 2

  • PROBLEM - ((B)):

5(2x + 6) = -4( -5 - 2x) + 3x

  • EXPAND THE EXPRESSION:

10x + 30 = -4( -5 - 2x) + 3x

  • APPLY THE DISTRIBUTIVE PROPERTY:

10x + 30 = 20 + 8x + 3x

  • REARRANGE THE TERMS:

10x + 30 = 20 + 11x

  • COMBINE LIKE TERMS:

10x - 11x = 20 - 30

  • CALCULATE:

-x = 20 - 30

-x = -10

  • DIVIDE BOTH SIDES OF THE EQUATION:

x = 10

  • DRAW THE CONCLUSION(s):

HENCE,

((A)): -5(4x - 2 ) = -2(3 + 6x): X = 2

((B)): 5(2x + 6) = -4( -5 - 2x) + 3x: X = 10

I hope this helps you!

User Havaligi Sathish
by
8.3k points

No related questions found