Question

Moles present in 2g of CO

Answer 1

0.0714 mol CO or
`7.14 * 10^(-2)` mol

Step-by-step explanation:

1. C = 12.01 g/mol

2. O = 16.00 g/mol

3. 12.01 g/mol + 16.00 g/mol = 28.01 g/mol

4.
`(28.01 g)/(1 mol CO) = (2 g)/(x mol CO)`

5. 28.01x = 2

6. x = 2/28.01

7. x = 0.0714 mol or 7.14 *
`10^(-2)` mol