Question

In rectangle abcd above the angle a=45x bc=3x and cd=x+8determine the perimeter of the rectangle

Answer 1

To find the perimeter of the rectangle, we need to add up the lengths of all four sides. Let's break it down step by step:

Step 1: Identify the given measurements

The problem states that angle A is 45 degrees, BC is 3x, and CD is x + 8.

Step 2: Determine the lengths of the sides

Since angle A is 45 degrees and opposite sides of a rectangle are equal in length, we can conclude that side AB is also 3x.

Step 3: Find the length of side AD

Since the opposite sides of a rectangle are equal in length, side AD is also 3x.

Step 4: Calculate the perimeter

To find the perimeter, we add up the lengths of all four sides:

Perimeter = AB + BC + CD + AD

= 3x + 3x + (x + 8) + 3x

= 9x + x + 8

= 10x + 8

So, the perimeter of the rectangle is 10x + 8.

~~Alli~~

Answer 2

32

Explanation:

45x = 90

x = 2

BC = 3x = 3 × 1 = 6

CD = x + 8 = 2 + 8 = 10

perimeter = 2(BC + CD) = 2(6 + 10) = 2(16) = 32