To find the equation of the line with a slope of 3 passing through the point (-3,5), we will use the point-slope form of a linear equation, which is:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the line.
Plugging in the values, we have:
y - 5 = 3(x - (-3))
Simplifying, we get:
y - 5 = 3(x + 3)
Next, we distribute the 3 to both terms inside the parentheses:
y - 5 = 3x + 9
Finally, we isolate the y term by adding 5 to both sides:
y = 3x + 9 + 5
Simplifying further, we get:
y = 3x + 14
Therefore, the equation of the line with a slope of 3 passing through the point (-3,5) is y = 3x + 14.