Final answer:
To determine the dimensions of the rectangle with specific properties related to its width and diagonal, the Pythagorean Theorem is used. After setting up and solving the equation, it is found that the rectangle's dimensions are 3 inches in length, 4 inches in width, and 5 inches diagonally.
Step-by-step explanation:
To find the dimensions of a rectangle where the width is 1 inch more than the length and the diagonal is 2 inches longer than the length, we must set up equations based on the Pythagorean Theorem as follows:
Let the length be L inches.
Then, the width will be L + 1 inches.
The diagonal will be L + 2 inches.
According to the Pythagorean Theorem, L2 + (L + 1)2 = (L + 2)2
We expand and simplify this equation to find the value of L:
L2 + L2 + 2L + 1 = L2 + 4L + 4
Combining like terms, we get 2L2 + 2L + 1 = L2 + 4L + 4
Subtract L2 + 4L + 4 from both sides, we get L2 - 2L - 3 = 0
Factoring the quadratic equation, (L - 3)(L + 1) = 0, giving us the solutions L = 3 or L = -1. Since a negative length does not make sense in this context, we discard L = -1.
So, the dimensions of the rectangle are:
Length = 3 inches
Width = 3 + 1 = 4 inches
Diagonal = 3 + 2 = 5 inches