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A circle of radius 5cm has a chord 4cm from the centre of the circle. the length of the chord is​

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Answer: The length of the chord is 6 cm.

Explanation:

The length of the chord can be determined using the Pythagorean theorem.

Since the chord is 4 cm away from the center of the circle, it forms a right triangle with the radius of the circle as the hypotenuse and the distance from the center to the chord as one of the legs.

Let's label the radius as "r" and the distance from the center to the chord as "d".

Using the Pythagorean theorem, we have:

r^2 = d^2 + (length of the chord/2)^2

In this case, the radius (r) is given as 5 cm, and the distance from the center to the chord (d) is given as 4 cm.

Substituting the values into the equation, we get:

(5 cm)^2 = (4 cm)^2 + (length of the chord/2)^2

25 cm^2 = 16 cm^2 + (length of the chord/2)^2

9 cm^2 = (length of the chord/2)^2

To find the length of the chord, we take the square root of both sides:

√9 cm^2 = √(length of the chord/2)^2

3 cm = length of the chord/2

Multiplying both sides by 2, we get:

6 cm = length of the chord

Therefore, the length of the chord is 6 cm.

User Momen Zalabany
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