Question

If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g. °C) that can be heated from 22.5°C to 120.0°C?

Answer 1

To find the mass of iron that can be heated with a given amount of heat, use the formula m = heat / (c * ΔT), where m is the mass, c is the specific heat, and ΔT is the change in temperature. Substituting the values, the mass of iron is approximately 18.24 g.

Step-by-step explanation:

To calculate the mass of iron that can be heated from 22.5°C to 120.0°C using 801 J of heat, we can use the formula:

heat = mcΔT

where m is the mass of the iron, c is the specific heat of iron, and ΔT is the change in temperature. Rearranging the formula, we have:

m = heat / (c * ΔT)

Substituting the given values, we have:

m = 801 J / (0.450 J/g.°C * (120.0°C - 22.5°C))

m = 801 J / (0.450 J/g.°C * 97.5°C)

m = 801 J / 43.875 J/g

m ≈ 18.24 g

Answer 2

By using the heat transfer formula Q = mcΔT, the mass of iron that can be heated from 22.5°C to 120.0°C with 801 J of heat is calculated to be approximately 18.26 grams.

Step-by-step explanation:

To calculate the mass of iron that can be heated from 22.5°C to 120.0°C using 801 J of heat, we can employ the formula for heat transfer Q = mcΔT, where Q is the heat added, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

First, we determine the temperature change ΔT:

ΔT = (120.0 - 22.5) °C

ΔT = 97.5 °C

We then rearrange the formula to solve for the mass m:

m = Q / (c ΔT)

Substituting the given values into the equation, we have:

m = 801 J / (0.450 J/g°C × 97.5 °C)

m = 801 J / (43.875 J/g)

m = 18.26 g

Therefore, the mass of iron that can be heated is approximately 18.26 grams.