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A large cruise ship of mass 6.60 107 kg has a speed of 12.6 m/s at some instant.

(a) What is the ship's kinetic energy at this time?
(b) How much work is required to stop it? (Include the sign of this value.)
(c) What is the magnitude of the constant force required to stop it as it undergoes a displacement of 2.60 km?

User Bineteri
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1 Answer

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Step-by-step explanation:


k.e = (1)/(2) m {v}^(2)

m= 6.60107 kg, v= 12.6 m/s

K.E= 524 Joules

(b)


w = m {v}^(2)

W= 1048 Joules

(c)


f = (w)/(d)

F= 0.4 N

User Georg
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