Question

Use the slope-intercept form to write an equation of the line with the given properties. slope -6; passes through (5.0) O y = 6x - 30 Оy=- бх - 30 O y=-6(x + 5) O y=- 6x + 30 y = 6x + 30 Next > Previous

Answer 1

y = 6x - 30

Explanation:

Slope: -6

Point: (5, 0)

Step 1. Write the equation in slope-intercept form

y = 6x + b

Step 2. Use the point to find the value of b (y-intercept)

y = 6x + b

(0) = 6(5) + b

0 = 30 + b

b = 0 - 30

b = -30

Equation: y = 6x - 30

Answer 2

y = -6x +30

Explanation:

Hi! Our task is to find the equation of the line, given that:

• its slope is -6
• it passes through (5,0)

We'll plug these data into point-slope and later, simplify to slope intercept.

`y-y_1=m(x-x_1)` <- This is point slope.

`y-0=-6(x-5)` <- We will now distribute the -6.

`y-0=-6x+30` <- Simplify the left side.

`y=-6x+30`

Therefore, the equation for this line is y = -6x + 30.