Question

For the function, f(x) = x^2-3x+4, f(-2) =

Answer 1

f(x) = x^2 - 3x + 4
f(-2) = (-2)^2 - 3(-2) + 4
f(-2) = 4+6+4
f(-2) = 14

Answer 2

f(-2) = 14

Explanation:

Hi ! Our task is to evaluate f(-2) for the function
`\sf{f(x)=x^2-3x+4}`.

Replace x with -2:

`\sf{f(-2)=(-2)^2-3(-2)+4}`

`\sf{f(-2)=4+6+4}`

`\sf{f(-2)=10+4}`

`\boxed{\sf{f(-2)=14}}`