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Vrite an equation of the circle with center (3,-4) and radius 11.

User Yazh
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Answer:

(x - 3)^2 + (y + 4)^2 = 121

Explanation:

Given the the coordinates of the center and the radius, we can find the general equation of the circle, whose general equation is given by:

(x - h)^2 + (y - k)^2 = r^2, where

  • (h, k) are the coordinates of the center,
  • and r is the radius.

Thus, we can find the general equation of the circle by substituting (3, -4) for (h, k) and 11 for r:

(x - 3)^2 + (y - (-4))^2 = 11^2

(x - 3)^2 + (y + 4)^2 = 121

Thus, (x - 3)^2 + (y + 4)^2 = 121 is the equation of the circle with center (3, -4) and radius 11.

User Mehatab
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