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What is the relationship between the thickness of spring and the elastic potential energy possessed by the spring?

User Jpriebe
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Final answer:

The thickness of a spring is related to the elastic potential energy possessed by the spring according to Hooke's law. The elastic potential energy of a spring is directly proportional to the square of its displacement from its undeformed position.

Step-by-step explanation:

The relationship between the thickness of a spring and the elastic potential energy possessed by the spring is described by Hooke's law. Hooke's law states that the force applied to a spring is directly proportional to the displacement of the spring. This means that the elastic potential energy of a spring is directly proportional to the square of its displacement from its undeformed position. Mathematically, the elastic potential energy (PEs) of a spring can be calculated using the formula: PEs = 1/2kx2, where k is the spring constant and x is the displacement from the spring's undeformed position.

User Norine
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