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Log3- log2÷log 9 - log4​

Log3- log2÷log 9 - log4​
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Log3- log2÷log 9 - log4​

User Leaha
by
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1 Answer

1 vote

Answer:

1/2

Explanation:


(log 3 - log 2)/(log 9 - log 4)

Use logarithmic property: log xʸ = y log x.


(log 3 - log 2)/(log 3^2 - log 2^2)\\\\(log 3 - log 2)/(2 log 3 - 2 log 2)\\\\(log 3 - log 2)/(2 (log 3 - log 2))\\\\(1)/(2)

User Suada
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