Question

Largest two digit number divisible by both 2 and 3 is =?​

Answer 1

The largest two-digit number divisible by both 2 and 3 can be found by finding the common multiple of 2 and 3 that is less than 100.

To find the common multiple of 2 and 3, we can multiply the two numbers together. In this case, 2 multiplied by 3 is 6.

Next, we need to find the largest two-digit number that is divisible by 6. We can do this by dividing 99 by 6.

When we divide 99 by 6, we get a quotient of 16 and a remainder of 3.

Since we are looking for the largest two-digit number, we need to subtract the remainder (3) from 99 to get the final answer.

99 - 3 = 96

Therefore, the largest two-digit number divisible by both 2 and 3 is 96.

Explanation:

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Answer 2

- The largest two-digit number divisible by both 2 and 3 is 18.

Explanation:

To find the largest two-digit number divisible by both 2 and 3, we need to find the largest common multiple of 2 and 3 within the range of two-digit numbers.

The multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, ...

The multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, ...

From the list, we can see that the largest common multiple of 2 and 3 within the range of two-digit numbers is 18.

Therefore, the largest two-digit number divisible by both 2 and 3 is 18.

To summarize:

- The largest two-digit number divisible by both 2 and 3 is 18.