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Construct a parallelogram PQRS in which PQ = 5.8 cm, PS = 4.2 cm and

PSR = 65°. Measure and write down the lengths of the diagonals PR and
QS. (Please help 100 points)

User Tattvamasi
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1 Answer

5 votes

Answer:

To construct a parallelogram PQRS, follow these steps:

1. Draw a line segment PQ with a length of 5.8 cm.

2. From point P, draw a ray at an angle of 65°. This ray represents the side PS.

3. Measure 4.2 cm along this ray from point P and mark the endpoint as S.

4. Draw a line segment SR parallel to PQ and passing through point S.

5. Draw a line segment PR connecting points P and R.

6. Draw a line segment QS parallel to PR and passing through point S.

Now, to find the lengths of the diagonals PR and QS, you can use the properties of a parallelogram.

1. Diagonal PR:

- Since PQRS is a parallelogram, opposite sides are equal in length.

- Therefore, PR = PQ = 5.8 cm.

2. Diagonal QS:

- In a parallelogram, opposite angles are equal.

- Since angle PSR is 65°, angle PQR (opposite angle) is also 65°.

- Using the Law of Cosines, you can find the length of QS:

QS^2 = PQ^2 + PS^2 - 2 * PQ * PS * cos(PQR)

QS^2 = 5.8^2 + 4.2^2 - 2 * 5.8 * 4.2 * cos(65°)

QS ≈ 8.36 cm

So, the lengths of the diagonals PR and QS are approximately 5.8 cm and 8.36 cm, respectively

Explanation:

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User Elpita
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