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The equation of a circle C'is (= + 2)? + (y - 7)? = 36. What is its center (h, k)?

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answer:

To find the center of the circle, we need to identify the values of h and k in the equation of the circle C': (x - h)^2 + (y - k)^2 = r^2.

In this case, the given equation is (x + 2)^2 + (y - 7)^2 = 36. By comparing this equation to the standard equation of a circle, we can determine the values of h and k.

From the equation, we can see that (h, k) = (-2, 7).

Therefore, the center of the circle C' is (-2, 7).

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User Deepak Bhatia
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