The angle 2) P is congruent to angle S would be necessary. Therefore, 2) Angle P is congruent to angle S is correct.
Since side NP and side QS both equal 8, we already know that side NP is congruent to side QS.
It is also known that angle N is 40°, so angle N of triangle NOP should correspond to angle Q in triangle QRS.
These three values are necessary for the Angle-side-angle congruence theorem (ASA) to be applicable. One of the values should be a side.
The other two values should be angles.
The additional information required to demonstrate that triangle NOP is congruent to triangle QRS by the ASA theorem is a second angle.
We are interested in two angles as well as the included side.
(*Note: The term "included side" refers to the fact that the endpoints are measured angles; for instance, endpoints of NP would be angle N and angle P, and endpoints of QS would be angle Q and angle S.)
The side we are given (NP/QS) must be BETWEEN two congruent angles in order to demonstrate the angle-side-angle congruence theorem.
The angle 2) P is congruent to angle S would be necessary.
Question
Angle N=40 degrees, side NP=8 , angle Q=40 degrees, and side QS=8 What additional information would you need to prove that △ NOP=△ QRS by ASA .
1)Angle O is congruent to angle R .
2)Angle P is congruent to angle S .
3)Side NO is congruent to side QR.
4)Side OP is congruent to side RS.