Answer:
A Pythagorean triplet consists of three positive integers a, b, and c, where a^2 + b^2 = c^2. One of the numbers is given as 6, let's find the other two numbers:
Let's assume that 6 is one of the legs of the right triangle (a), and the other leg is b, and the hypotenuse is c.
According to the Pythagorean theorem:
a^2 + b^2 = c^2
Substitute the given value of a = 6:
6^2 + b^2 = c^2
36 + b^2 = c^2
Now let's find a Pythagorean triplet where the hypotenuse is c and one of the legs is 6. We can try different values for b until we find a square number that matches c^2 - 36.
Let's try b = 8:
36 + 8^2 = c^2
36 + 64 = c^2
100 = c^2
Taking the square root of both sides:
c = √100
c = 10
So, the Pythagorean triplet with one number as 6 is (6, 8, 10).