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the present age of a mother is three times that of her daughter, 5 years ago the mother's age was 7 times that of a daughter. determine the present ages.​

User Vahn Marty
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Answer:

Let's denote the present age of the daughter as "D" and the present age of the mother as "M."

According to the given information:

1. The present age of the mother is three times that of her daughter:

M = 3D

2. Five years ago, the mother's age was 7 times that of the daughter:

M - 5 = 7(D - 5)

Now we can use these two equations to solve for the present ages of the daughter and the mother.

Substitute the value of M from the first equation into the second equation:

3D - 5 = 7(D - 5)

Distribute and solve for D:

3D - 5 = 7D - 35

4D = 30

D = 30 / 4

D = 7.5

Now that we have the age of the daughter, we can use the first equation to find the age of the mother:

M = 3D

M = 3 * 7.5

M = 22.5

However, ages are typically considered whole numbers, so we need to adjust our solution.

If we assume that the daughter is 7 years old and the mother is 21 years old, then:

Present age of daughter (D) = 7 years

Present age of mother (M) = 21 years

And if you want ages in whole numbers, you can use the first equation to find other possible integer solutions. For example, if the daughter is 3 years old, the mother would be 9 years old. The specific ages would depend on the context and assumptions you make.

User Duck Degen
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