151k views
3 votes
Two small plastic spheres are given positive electrical charges. When they are a distance of 15.2 cm apart, the repulsive force between them has a magnitude of 0.215 N. You may want to review (Page). For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Force between two point charges. What is the charge on each sphere if the two charges are equal? What is the charge on the first sphere it it equals one-quarter the charge of the second sphere? Express your answer in coulombs. VO AXO ? с Submit Request Answer Part What is the charge on the second sphere described in the previous part?

1 Answer

1 vote

If the charges on the two spheres are equal, each sphere has a charge of approximately 0.06 Coulombs.
- If the charge on the first sphere is one-quarter the charge of the second sphere, the charge on the second sphere is approximately 0.12 Coulombs.

To find the charge on each sphere, we can use Coulomb's Law, which states that the magnitude of the electrostatic force between two charged objects is given by the equation:

F = k * (|q1| * |q2|) / r^2

where F is the force, k is the electrostatic constant (k = 8.99 x 10^9 N*m^2/C^2), |q1| and |q2| are the magnitudes of the charges on the two spheres, and r is the distance between them.

In the given problem, the force (F) between the two spheres is 0.215 N and the distance (r) between them is 15.2 cm (or 0.152 m).

First, let's assume that the charges on the two spheres are equal. We can substitute the known values into the Coulomb's Law equation:

0.215 N = (8.99 x 10^9 N*m^2/C^2) * (|q1| * |q1|) / (0.152 m)^2

Simplifying this equation, we find:

|q1|^2 = (0.215 N * (0.152 m)^2) / (8.99 x 10^9 N*m^2/C^2)

|q1|^2 ≈ 0.00363 C^2

Taking the square root of both sides, we get:

|q1| ≈ 0.06 C

Therefore, if the charges on the two spheres are equal, each sphere has a charge of approximately 0.06 Coulombs.

Now, let's consider the scenario where the charge on the first sphere is one-quarter the charge of the second sphere. Let's assume the charge on the second sphere is q2.

Using the same equation and substituting the known values:

0.215 N = (8.99 x 10^9 N*m^2/C^2) * ((1/4) * q2 * q2) / (0.152 m)^2

Simplifying this equation, we find:

q2^2 = (4 * 0.215 N * (0.152 m)^2) / (8.99 x 10^9 N*m^2/C^2)

q2^2 ≈ 0.0145 C^2

Taking the square root of both sides, we get:

q2 ≈ 0.12 C

Therefore, if the charge on the first sphere is one-quarter the charge of the second sphere, the charge on the second sphere is approximately 0.12 Coulombs.

User Helpdesk
by
7.8k points