Answer:
≈ 14,8
Explanation:
We have X(1 ; 6) ; Y(3 ; 1) and Z(6 ; 3)
XY = √((3 - 1)² + (1 - 6)²)
XY = √((2)² + (-5)²)
XY = √(4 + 25)
XY = √29
XZ = √((6 - 1)² + (3 - 6)²)
XZ = √((5)² + (-3)²)
XZ = √(25 + 9)
XZ = √34
YZ = √((6 - 3)² + (3 - 1)²
YZ = √((3)² + (2)²)
YZ = √(9 + 4)
YZ = √13
We have p = √29 + √34 + √13 ≈ 14,8 ⇒ answer D